Answer:
[tex]v_{avg} = 3.36 m/s[/tex]
S.I unit is m/s
numeral value is 3.36
Given:
displacement, d = 13 m
displacement, d' = - 3.1 m
displacement, d'' = 21 m
time, t = 2.8 s
time, t' = 1.4 s
time, t'' = 5 s
Solution:
The average velocity of a body is given by:
[tex]v_{avg} = \frac{Total distance traveled or total displacement}{Total time taken}[/tex]
[tex]v_{avg} = \frac{d + d'+ d''}{t +t'+t''}[/tex]
[tex]v_{avg} = \frac{13 - 3.1 + 21}{2.8 + 1.4 + 5} = 3.36 m/s[/tex]
where
Total distance traveled = |d| + |d'| + |d''| = 13 + 3.1 + 21 = 37.1 m
Total displacement = d + d' + d'' = 13 - 3.1 + 21 = 30.9 m
