Answer:
[tex]0.25\ hour[/tex] or [tex]15\ min[/tex]
Step-by-step explanation:
Let
d -----> the distance in miles
t -----> the time in hours
s -----> the speed in miles per hour
so
[tex]s=\frac{d}{t}[/tex]
Solve for t
[tex]t=\frac{d}{s}[/tex]
we have
[tex]d=7.5\ mi[/tex]
[tex]s=30\ mi/h[/tex]
substitute the values
[tex]t=\frac{7.5}{30}[/tex]
[tex]t=0.25\ hour[/tex]
Convert to minutes
[tex]0.25\ hour=0.25*60=15\ min[/tex]