Answer:
[tex]1.25[/tex] ounes of [tex]1[/tex]% and [tex]3.75[/tex] ounes of [tex]5[/tex]% will be used to make a [tex]5[/tex]-ounce tube
Explanation:
let "x" represent the number of ounces of [tex]1[/tex]% concentration
Then the number of ounces of [tex]5[/tex]%concentration would be [tex]5-x[/tex]
Now the total of ounces of [tex]1[/tex]% and [tex]5[/tex]% would be equal to [tex]5[/tex]-ounce of [tex]4[/tex]% hydrocortisone.
so the equation will be
[tex]0.01 (x) + 0.05(5-x) = 0.04*5\\0.01x-0.05x+0.25= 0.2\\\\0.25-0.2= 0.04x\\x = \frac{0.05}{0.04} \\x= 1.25\\5-x= 5-1.25 = 3.75[/tex]
hence
[tex]1.25[/tex] ounes of [tex]1[/tex]% and [tex]3.75[/tex] ounes of [tex]5[/tex]% will be used to make a [tex]5[/tex]-ounce tube