Answer:
d = 250 m
Explanation:
As we know that car starts from rest while truck is moving at constant speed
so let say after time t they both passes through the same point
so we have
[tex]d_{truck} = d_{car}[/tex]
[tex]20 t = \frac{1}{2}(3.20) t^2[/tex]
[tex]20t = 1.6 t^2[/tex]
[tex]t = \frac{20}{1.6}[/tex]
[tex]t = 12.5 s[/tex]
so the distance moved by the truck or the car in the above time is given as
[tex]d = vt[/tex]
[tex]d = 20\times 12.5[/tex]
[tex]d = 250 m[/tex]