A total of 267 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student tickets sold was two times the number of adult tickets sold. How many adult tickets were sold?

Respuesta :

Answer:

the number of adult tickets sold is

x = 89

and , the number of student tickets sold is y = 178

Step-by-step explanation:

Let the number of adult tickets sold be x and number of student tickets sold be y !

Given, :- Total 267 tickets were sold

i.e, x + y = 267

x = 267 - y .... ( i )

Also, The number of student tickets sold was two times the number of adult tickets sold.

i.e, y = 2x ...... ( ii )

putting value of x from ( i ) in ( ii )

y = 2 ( 267 - y )

y = 534 - 2y

3y = 534

y = 534/3

y = 178

also, x = 267 - y

x = 267 - 178

x = 89

So, the number of adult tickets sold is

x = 89

and , the number of student tickets sold is y = 178

Using a system of equations, it is found that 89 adult tickets were sold.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are:

  • Variable x: Number of adult tickets sold.
  • Variable y: Number of student tickets sold.

A total of 267 tickets were sold for the school play, hence:

[tex]x + y = 267[/tex]

The number of student tickets sold was two times the number of adult tickets sold, hence:

[tex]y = 2x[/tex]

Replacing on the first equation:

[tex]x + y = 267[/tex]

[tex]x + 2x = 267[/tex]

[tex]x = \frac{267}{3}[/tex]

[tex]x = 89[/tex]

89 adult tickets were sold.

To learn more about system of equations, you can take a look at https://brainly.com/question/24342899