Explanation:
Also, we know that molarity is the number of moles present in a liter of solution.
Molarity = [tex]\frac{\text{no. of moles}}{volume}[/tex]
0.05 m = [tex]\frac{\text{no. of moles}}{0.25 L}[/tex] (as 1 ml = 0.001 L)
no. of moles = 0.0125 mol
It is known that number of moles equal mass divided by molar mass. And, molar mass of KOH is 56.10 g/mol.
Hence, No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
0.0125 mol = [tex]\frac{mass}{56.10 g/mol}[/tex]
mass = 0.701 g
Thus, we can conclude that there are 0.701 g of KOH are there in 250 milliliters of 0.05m aqueous solution of this substance.
