Answer:
The first three terms of the sequence is 16,49,148.
Step-by-step explanation:
Given : Function [tex]f(x)=3x+1[/tex], starting with x=5.
To find : What are the first three terms of the sequence defined by function ?
Solution :
To find the first three terms of the sequence, substitute the value of x in the function.
[tex]f(x)=3x+1[/tex]
Input at x=5,
[tex]f(5)=3(5)+1[/tex]
[tex]f(5)=15+1[/tex]
[tex]f(5)=16[/tex]
Input at x=16,
[tex]f(16)=3(16)+1[/tex]
[tex]f(16)=48+1[/tex]
[tex]f(16)=49[/tex]
Input at x=49,
[tex]f(49)=3(49)+1[/tex]
[tex]f(49)=147+1[/tex]
[tex]f(49)=148[/tex]
Therefore, The first three terms of the sequence is 16,49,148.
