Ok. What number raised to the 5th power yields 32?
How about 2?
2 x 2 x 2 x 2 x 2 = 2^(1 + 1 + 1 + 1 + 1).
Answer: 2^(5).
Got it?
The exponent form of given integer is equal to [tex](2)^{5}[/tex] with base [tex]2[/tex] and exponent [tex]5[/tex].
" Integer is defined as the set of all whole numbers and negative numbers."
Formula used
[tex]a^{m} \times a^{m} = a^{m +m}[/tex]
According to the question,
Given integer,
[tex]32[/tex]
Express given integers into the product of prime factors and apply formula we get,
[tex]32 = 2 \times 2\times 2\times 2\times 2[/tex]
[tex]= 2^{(1+1+1+1+1)} \\\\= 2^{(5)}[/tex]
Base [tex]= 2[/tex]
Exponent [tex]= 5[/tex]
Hence, the exponent form of given integer is equal to [tex](2)^{5}[/tex] with base [tex]2[/tex] and exponent [tex]5[/tex].
Learn more about integers here
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