Answer:
so pressure in A must be one third the pressure in B
Explanation:
We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of mole will also be same .
For cylinder A
Temperature T , volume 3V , pressure P₁ , no of mole = n
so
P₁ X 3V = n R T
For cylinder B
Temperature T , volume V , pressure P₂ ,no of mole = n
so
P₂ X V = n R T
From the two equation above
P₁ X 3V = P₂ X V
[tex]\frac{P_1}{P_2}=\frac{1}{3}[/tex]
P₁ = P₂ / 3
so pressure in A must be one third the pressure in B