Answer: 0.02055867
Step-by-step explanation:
Given : [tex]H_0: \mu=50\\\\ H_a: \mu\neq 50[/tex], since the alternative hypothesis is two-tailed , so the test is a two tailed test.
Sample size : n= 30
Degree of freedom for t-distribution = [tex]df=n-1=30-1=29[/tex]
Test statistic= t= -2.43
By using the normal t-distribution table ( or calculator ) , we have
The corresponding P-value for two tailed test = 0.02055867