Answer: 0.0108
Step-by-step explanation:
Given : [tex]H_0:\mu=50\\\\H_a:\mu>50[/tex]
Since the alternative hypotheses is right-tailed, so the test is a right-tailed test.
Sample size : n=30
The degree of freedom for t-distribution= [tex]=n-130-1=29[/tex]
The by using the normal t-distribution table , we have
The P-value corresponds to t-statistic vale 2.43 and degree of freedom 29 , is 0.01075997 i.e. approximately 0.0108