I2 is produced by the reaction of 0.4235 mol of CuCl2 to the following euation:
2CuCl2 + 4KI ? 2CuI + 4KCl + I2
(a) How many molecules of I2 are produced?
(b) What mass of I2 is produced?

Respuesta :

Answer:

For a: The number of molecules of iodine gas produced are [tex]1.275\times 10^{23}[/tex]

For b: The mass of iodine gas is produces is 26.9 grams.

Explanation:

We are given:

Moles of copper (II) chloride = 0.4235 moles

For the given chemical reaction:

[tex]2CuCl_2+4KI\rightarrow  2CuI+4KCl+I_2[/tex]

By Stoichiometry of the reaction:

2 moles of copper (II) sulfate produces 1 mole of iodine gas

So, 0.4235 moles of copper (II) sulfate will produce = [tex]\frac{1}{2}\times 0.4235=0.2118mol[/tex] of iodine gas

  • For a:

According to mole concept:

1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules

So, 0.2118 moles of compound will contain = [tex]0.2118\times 6.022\times 10^{23}=1.275\times 10^{23}[/tex] number of molecules

Hence, the number of molecules of iodine gas produced are [tex]1.275\times 10^{23}[/tex]

  • For b:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

We are given:

Moles of iodine gas = 0.2118 moles

Molar mass of iodine gas = 127 g/mol

Putting values in above equation, we get:

[tex]0.2118mol=\frac{\text{Mass of iodine gas}}{127g/mol}\\\\\text{Mass of iodine gas}=(0.2118mol\times 127g/mol)=26.9g[/tex]

Hence, the mass of iodine gas is produces is 26.9 grams.

0.4235 moles of CuCl₂ produce 1.275 × 10²³ molecules of I₂, which have a mass of 53.76 g.

Let's consider the following balanced equation.

2 CuCl₂ + 4 KI ⇒ 2 CuI + 4 KCl + I₂

The molar ratio of CuCl₂ to I₂ is 2:1. The moles of I₂ produced from 0.4235 moles of CuCl₂ are:

[tex]0.4235 mol CuCl_2 \times \frac{1molI_2}{2molCuCl_2} = 0.2118molI_2[/tex]

We will convert 0.2118 moles of I₂ to molecules using Avogadro's number.

[tex]0.2118mol \times \frac{6.022 \times 10^{23}molecules }{mol} = 1.275 \times 10^{23}molecules[/tex]

Finally, we will convert 0.2118 moles of I₂ to grams using its molar mass.

[tex]0.2118mol \times \frac{253.81g}{mol} = 53.76 g[/tex]

0.4235 moles of CuCl₂ produce 1.275 × 10²³ molecules of I₂, which have a mass of 53.76 g.

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