Respuesta :
Answer:
a) [tex]HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O[/tex]
b) [tex]H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)[/tex]
c) [tex]Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O[/tex]
Explanation:
a)
when [tex]HClO_4[/tex] is added to LiOH, lithium chlorate and water is formed.
[tex]HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O[/tex]
Balancing of above reaction,
It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.
(b) When aqueous [tex]H_2SO_4[/tex] is added to NaOH, [tex]Na_2SO_4[/tex] and [tex]H_2O[/tex] is formed. It is a neutrilization reaction.
[tex]H_2SO_4(aq) + NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)[/tex]
Balancing of above reaction,
First balance all the atoms except O and H
S atom is already balanced in either side
No. of Na atom in left hand side = 1
No. of Na atom in right hand side = 2
So multiply NaOH by 2, now the reaction becomes:
[tex]H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)[/tex]
No. of O atoms in left hand side = 6
No. of O atoms in right hand side = 5
So multiply H2O by 2, now the reaction becomes:
[tex]H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)[/tex]
Now, it can been seen that all the atoms are balanced.
c) When [tex]Ba(OH)2[/tex] reacts with HF, baroum fluoride and water is formed.
[tex]Ba(OH)2 + HF\rightarrow BaF_2 + H_2O[/tex]
Balancing of above reaction,
Barium atoms are already balanced on either side.
No. of F atoms on left hand side = 1
No. of F atoms on right hand side = 2
So, multiply HF by 2, now reaction becomes
[tex]Ba(OH)2 + 2HF\rightarrow BaF_2 + H_2O[/tex]
In order to balance H and O on either side, multiply H2O by 2.
[tex]Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O[/tex]
An acid base reaction always results in the formation of salt and water.
An acid reacts with a base to yield salt and water. This is called a neutralization reaction. The balanced reaction equation must take into cognizance the number of atoms of each element on both sides of the reaction equation.
The balanced reaction equation in each case is;
- HClO4(aq) + LiOH(aq) ------> LiClO4(aq) + H2O(l)
- H2SO4 (aq) + 2NaOH(aq) ---------> Na2SO4 (aq) + 2H2O(l)
- 2HF(g) + Ba(OH)2(aq) --------> BaF2(aq) + 2H2O(l)
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