Answer:
Q= 65.57 W
Explanation:
Given that
Outer diameter=12 cm
Thickness = 2.5 cm
So inner diameter = 7 cm
Outer wall temperature =100° C
Outer surface of insulation = 20 °C
As we know that thermal resistance of cylinder pipe is given as follows
[tex]R_{th}=\dfrac{ln\frac{r_2}{r_1}}{2\pi Kl}[/tex]
Now by putting the values
Lets put l = 1 m because given that find heat loss per unit length
[tex]R_{th}=\dfrac{ln\frac{6}{3.5}}{2\pi \times 0.07\times 1}[/tex]
So
[tex]R_{th}=1.22 \frac{W}{m-K}[/tex]
now heat loss Q
[tex]Q=\dfrac{\Delta T}{R_{th}}[/tex]
[tex]Q=\dfrac{100-20}{1.22}[/tex]
Q= 65.57 W