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Considered this question: what is the mass of solute in 200.0 L of a 1.556-M solution of KBR?
(a) Outline the steps necessary to answer the question
(b) Answer the question

Respuesta :

Willchemistry

Hey there!:

a )

number of moles of solute :

moles of solute = molarity  x volume ( L )

moles of solute = 1.556 x 200.0

moles of solute = 311.2 moles of  KBr

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b) Molar mass of KBr : 119.002 g/mol

1 mole KBr ----------------- 119.002 g

311.2 moles ---------------------- ( mass KBr ) ?

mass glucose = 311.2 x 119.002 / 1

mass glucose => 37033.4224 g

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