contestada

A 60-gram sample of LiCl · H 2 O is heated in an open crucible until all of the water was driven off. What is the total mass of LiCl remaining in the crucible

Respuesta :

Answer:

42.11 g

Explanation:

Mass of the hydrated salt = 60 g

The moles of the hydrated salt is :

Amount = 60 g

Molar mass of [tex]LiCl.H_2O[/tex] = 60.4093 g/mol

The formula for the calculation of moles is shown below:

[tex]moles=\frac {Mass\ taken}{Molar\ mass}[/tex]

Thus, moles are:

[tex]moles=\frac{60\ g}{60.4093\ g/mol}[/tex]

[tex]moles= 0.9932\ mol[/tex]

After heating only LiCl remains in the crucible. So,

Moles of LiCl = 0.9932 moles

Molar mass of [tex]LiCl[/tex] = 42.394 g/mol

The formula for the calculation of moles is shown below:

[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]

Also, mass is

[tex]Mass=moles\times Molar\ mass[/tex]

[tex]Mass=0.9932\times 42.394[/tex]

Total mass of LiCl remaining in the crucible = 42.11 g