Answer: Percent ammonia in [tex]Co(NH_3)_6Cl_3[/tex] is 38.2 % in 3 significant figures.
Explanation:
To calculate the mass percent of element in a given compound, we use the formula:
[tex]\text{Mass percent of ammonia}=\frac{\text{Mass of ammonia}}{\text{Molar mass of}Co(NH_3)_6Cl_3}\times 100[/tex]
Molar mass of [tex]Co(NH_3)_6Cl_3[/tex] = 267 g/mol
Mass of [tex]NH_3[/tex] = [tex]6\times 17g/mol=102g[/tex]
Thus [tex]\text{Mass percent of ammonia}}=\frac{102}{267}\times 100=38.2\%[/tex]
Thus percent ammonia in [tex]Co(NH_3)_6Cl_3[/tex] is 38.2 % in 3 significant figures.
