Answer
0.92265 nm
Explanation:
We have given electron transits from state 1 to state 9
So [tex]n_1=1[/tex] and [tex]n_2=9[/tex]
Now according to Bohr's rule [tex]\frac{1}{\lambda }=R\left ( \frac{1}{n_1^2}-\frac{1}{n_2^2}\right )[/tex] here R is Rydberg constant which value is 10973731.6 [tex]m^{-1[/tex]
So [tex]\frac{1}{\lambda }=10973731.6\left ( \frac{1}{1^2}-\frac{1}{9^2}\right )[/tex]
[tex]\frac{1}{\lambda }=10838253.43m^{-1}[/tex]
[tex]\lambda =9.2265\times 10^{-8}m=0.92265nm[/tex]
