Answer:
442.3 mL
Explanation:
Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:
[tex]M=\frac{Moles of substance X}{Volume of the solution}[/tex]
Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:
[tex]11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}[/tex]
Then you can solve for the volume of the solution:
[tex]Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL[/tex]
Hope it helps!
