Answer : The number of moles of gas present in container are 1.697 mole.
Explanation :
Using ideal gas equation,
[tex]PV=nRT[/tex]
where,
P = pressure of gas = 74 mmHg = 0.097 atm
conversion used : (1 atm = 760 mmHg)
V = volume of gas = 500.0 L
T = temperature of gas = [tex]75^oC=75+273=348K[/tex]
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.K
Now put all the given values in the ideal gas equation, we get the number of moles of gas in the container.
[tex](0.097atm)\times (500.0L)=n\times (0.0821L.atm/mole.K)\times (348K)[/tex]
[tex]n=1.697mole[/tex]
Therefore, the number of moles of gas present in container are 1.697 mole.
