Respuesta :
Answer:
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
Explanation:
Given;
1 mol of CH₄
0.6 mol of C₆H₆
0.4 Mol of C₃H₈.
Now,
moles = Mass / Molar mass
Thus,
for 1 mol of CH₄
1 = mass / ( 12 + 4 × (1) )
or
mass = 16 grams
now,
16 grams of CH₄ contains 4 grams of hydrogen
and, for 0.6 mol of C₆H₆
0.6 = Mass / ( 12 × 6 + 6 × 1)
or
Mass = 46.8 grams
Now,
78 grams of CH₄ contains 6 grams of hydrogen
thus,
46.8 grams of CH₄ will contain = (6 / 78) × 46.8 grams of hydrogen
or
46.8 grams of CH₄ will contain = 3.6 grams of hydrogen
and, for 0.4 Mol of C₃H₈
0.4 = mass / (3 × 12 + 8 × 1)
or
Mass of 0.4 Mol of C₃H₈ = 17.6 grams
Now,
44 grams of C₃H₈ contains 8 grams of hydrogen
thus,
17.6 grams of C₃H₈ will contain = ( 8 / 44 ) × 17.6 grams of hydrogen
or
17.6 grams of C₃H₈ will contain = 3.2 grams of hydrogen
Hence,
1 mol of CH₄ will contain greatest mass of the oxygen i.e 4 grams
Answer: 1 mole of methane has the greatest mass of hydrogen.
Explanation:
To calculate the mass of hydrogen, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For 1 mole of [tex]CH_4[/tex]
In 1 mole of methane, 1 mole of carbon atom and 4 moles of hydrogen atoms are there.
Molar mass of hydrogen = 1 g/mol
Moles of hydrogen = 4 moles
Putting values in equation 1, we get:
[tex]4mol=\frac{\text{Mass of hydrogen}}{1g/mol}\\\\\text{Mass of hydrogen}=4g[/tex]
The mass of hydrogen in 1 mole of [tex]CH_4[/tex] is 4 g
- For 0.6 mole of [tex]C_6H_6[/tex]
In 1 mole of benzene, 6 moles of carbon atoms and 6 moles of hydrogen atoms are there.
So, in 0.6 moles of benzene, (6 × 0.6) = 3.6 moles of carbon atoms and (6 × 0.6) = 3.6 moles of hydrogen atoms are there.
Molar mass of hydrogen = 1 g/mol
Moles of hydrogen = 3.6 moles
Putting values in equation 1, we get:
[tex]3.6mol=\frac{\text{Mass of hydrogen}}{1g/mol}\\\\\text{Mass of hydrogen}=3.6g[/tex]
The mass of hydrogen in 0.6 mole of [tex]C_6H_6[/tex] is 3.6 g
- For 0.4 mole of [tex]C_3H_8[/tex]
In 1 mole of [tex]C_3H_8[/tex], 3 moles of carbon atom and 8 moles of hydrogen atoms are there.
So, in 0.4 moles of [tex]C_3H_8[/tex], (3 × 0.4) = 1.2 moles of carbon atoms and (8 × 0.4) = 3.2 moles of hydrogen atoms are there.
Molar mass of hydrogen = 1 g/mol
Moles of hydrogen = 3.2 moles
Putting values in equation 1, we get:
[tex]3.2mol=\frac{\text{Mass of hydrogen}}{1g/mol}\\\\\text{Mass of hydrogen}=3.2g[/tex]
The mass of hydrogen in 0.4 mole of [tex]C_3H_8[/tex] is 3.2 g
Hence, 1 mole of methane has the greatest mass of hydrogen.
