Answer:
a)C2HBrClF3 = 197.35 g/mol
b)C12H14N2CL2 = 229.06g/mol
c)C8H10N4O2 = 194.22g/mol
d) CO(NH2)2=60.07 g/mol
e)C17H35CO2Na = 306.52 g/mol
Explanation:
Molar mass of a compound is equal to the sum of the atomic masses of the constituent elements.
a) C2HBrClF3
[tex]Molar\ mass = 2(At. mass C)+1(at.mass H) +1(At. mass Br) + 1(At.mass Cl) + 3(At.mass F)\\=2(12.01 g/mol) + 1(1.01g/mol)+1(79.90 g/mol) +1(35.45g/mol)+3(18.99g/mol)=197.35g/mol[/tex]
b) C12H14N2CL2
[tex]Molar\ mass = 12(C) + 14(H) + 2(N) + 2(Cl)\\\\=12(12.01) + 14(1.01) + 2(14.01) + 2(35.45) = 229.06g/mol[/tex]
c) C8H10N4O2
[tex]Molar\ mass = 8(C) + 10(H) + 4(N) + 2(O)\\\\=8(12.01) + 10(1.01) + 4(14.01) + 2(16.00) =194.22g/mol[/tex]
d) CO(NH2)2
[tex]Molar\ mass = 1(C) + 1(O) + 2(N) + 4(H)\\\\=1(12.01) + 1(16.00) + 2(14.01)+4(1.01) =60.07 g/mol[/tex]
e) C17H35CO2Na
[tex]Molar Mass = 18(C) + H(35) +2(O) + 1(Na)\\\\=18(12.01) + 35(1.01) + 2(16.00) + 1(22.99) =306.52 g/mol[/tex]
