-PLEASE HELP ME-

A veterinarian is changing the diets of two animals, Simba and Cuddles. Simba currently consumes 1,220 Calories per day. That number will increase by 130 Calories each day. Cuddles currently consumes 3,080 Calories a day. That number will decrease by 180 Calories each day. The patterns will continue until both animals are consuming same number of Calories each day. In how many days will that be? How many Calories will the animals be consuming each day then?

Respuesta :

Answer:   On the eighth day of diet both animals will be having same  calories.

1900 calories each animal will be consuming each day.

Answer:

They will both be consuming 2000 calories in 6 days.

Step-by-step explanation:

First you need to make an expression for each animal. x will represent the number of days.

Simba [tex]1220 + 130x[/tex]

Cuddles [tex]3080 - 180x[/tex]

These represent the number of calories they will be consuming on any given day. Since you want to know when they will be the same, you set them equal to each other, and solve for x.

[tex]1220+130x=3080-180x[/tex]

subtract 1220 from both sides

[tex]130x = 1860 - 180x[/tex]

add 180x to both sides

[tex]310x = 1860[/tex]

divide both sides by 310 to get x by itself

[tex]\frac{310x}{310} = \frac{1860}{310} \\ \\ x = 6[/tex]

to find out how many calories they will be eating on day 6, simply plug 6 in to either expression, since they will be the same.

[tex]1220 + 130 (x) \\ 1220 + 130(6)\\ 1220 + 780 \\ 2000[/tex]