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Which equation represents a line that passes through (5, 1) and has a slope of StartFraction one-half EndFraction?

y – 5 = y minus 5 equals StartFraction one-half EndFraction left-parenthesis x minus 1 right-parenthesis.(x –1)
y – y minus StartFraction one-half EndFraction equals 5 left-parenthesis x minus 1 right-parenthesis. = 5(x –1)
y – 1 = y minus 1 equals StartFraction one-half EndFraction left-parenthesis x minus 5 right-parenthesis.(x –5)
y – 1 = 5y minus 1 equals 5 left-parenthesis x minus StartFraction one-half EndFraction right-parenthesis.

Respuesta :

calculista

Answer:

y – 1 = y minus 1 equals StartFraction one-half EndFraction left-parenthesis x minus 5 right-parenthesis.(x –5)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=\frac{1}{2}[/tex]

[tex](5,1)[/tex]

substitute

[tex]y-1=\frac{1}{2}(x-5)[/tex]

akposevictor

The equation of the line in point-slope form is: y - 1 = 1/2(x - 5).

What is Equation of a Line in Point-slope form?

The point-slope form of the equation of a line is given as, y - b = m(x - a), where (a, b) is a point and m is the slope of the line.

Given:

  • (5, 1) = (a, b)
  • Slope = 1/2 = m

Plug in the values

y - 1 = 1/2(x - 5)

Therefore, the equation of the line in point-slope form is: y - 1 = 1/2(x - 5).

Learn more abut point-slope form on:

https://brainly.com/question/24907633