Answer:
Step-by-step explanation:
I can help you complete the square and solve the problem, but I'm going to have to leave it to you where and how to fill in your chart. Never saw one like that, at least in the books I teach from (where are Christian-based, so that might be why. I'm not common core. But completing the square is the same process, no matter what!)
Begin by subtracting 9 from both sides to isolate the x terms to get:
[tex]x^2-8x=-9[/tex]
Now we begin completing the square. The rules are to take half the linear term, square it, and add it to both sides. Our linear term is 8. Half of 8 is 4, and 4 squared is 16. So we add 16 to both sides:
[tex](x^2-8x+16)=-9+16[/tex]
This process has created a perfect square binomial on the left. We will state that binomial along with simplifying on the right:
[tex](x-4)^2=7[/tex]
If we move the 7 back over, this is the equation in vertex form. But to solve it, undo the square on the left by taking the square root of both sides:
x - 4 = ±[tex]\sqrt{7}[/tex]
Add 4 to both sides to get the 2 solutions:
x = 4 ±√7
