Answer:
A
Step-by-step explanation:
Given
p² + 2p - 8 = 0 ← in standard form
with a = 1, b = 2, c = - 8
Using the quadratic formula to solve for p
p = ( - 2 ± [tex]\sqrt{2^2-(4(1)(-8))}[/tex] / 2
= ( - 2 ± [tex]\sqrt{4+32}[/tex] / 2
= ( - 2 ± [tex]\sqrt{36}[/tex] ) / 2
p = [tex]\frac{-2-6}{2}[/tex] = [tex]\frac{-8}{2}[/tex] = - 4
p = [tex]\frac{-2+6}{2}[/tex] = [tex]\frac{4}{2}[/tex] = 2
Answer:
A. p = -4, p = 2.
Step-by-step explanation:
p^2 + 2p - 8 = 0
Using the quadratic formula;
p = [-2 +/- √(2^2 - 4*1*-8)] / 2
= (-2 +/- √36) / 2
= (-2 +/- 6) / 2
= 4/2 , -8/2
= 2, -4.
