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A meter stick whose mass is 330 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a force 9 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, , when you first apply the force?

Respuesta :

Manetho

Answer:

initial magnitude will be 9 N and direction will be to the right

Explanation:

force= 9N

mass m= 330 grams

acceleartion = a

from newtons 2nd law of motion we write

[tex]F= \frac{\mathrm{dP} }{\mathrm{d} t}[/tex]

dP is the chage in momentum dt is time taken and F is the Force applied

[tex]9N= \frac{\mathrm{dP} }{\mathrm{d} t}[/tex]

this shows that the rate of change of momentum is 9 N

we also know that F= ma

putting values we get

[tex]9= 0.330\times a[/tex]

a= 27.27 m/sec^2

The direction of acceleration will along the direction of force applied. So will be the direction of change momentum as in F=ma,  mass is the scalar quantity and direction of force dictates the direction of motion. Hence, initial magnitude will be 9N and direction will be to the right

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