Answer:
[tex]\Delta U= 2.03 * 10^6 J[/tex]
Explanation:
due to Isobaric system, the pressure is kept constant -
Work = Pressue( V_i - V_f)
WHERE
V_i IS INITIAL VOLUME
V_f is final volume
Work = 2.0*10^5 Pa (0.824 - 1.00x10^{-3})
Work = 1.64x10^5 J
B)
increase or decrease in internal energy can be calculated by using following relation:
[tex](\Delta U) = Q - W[/tex]
by keeping temperature and pressure constant, Q can be calculated from the phase change.
Q = (mass)(Heat of Vaporiztion)
Q = (1 kg)(2.20 *10^6) = 2.20 * 10^6 J
[tex](\Delta U) = Q - W[/tex]
[tex]\Delta U= 2.20x10^6 J - 1.64x10^5 J[/tex]
[tex]\Delta U= 2.03 * 10^6 J[/tex]