Answer:
Required probability equals 0.18%
Step-by-step explanation:
The probability that the primary and one auxiliary computer fails equals
1) Probability that A and B fails
2)Probability that A and C fails
Thus required probability equals
[tex]P(E)=P(1)(2)+P(1)P(3)\\\\P(E)=0.03\times 0.03+0.03\times 0.03P(E)=0.18%[/tex]