Answer:13.2,41.4,82.8 ft
Explanation:
Given Person is 6.60 ft from the left hand side mirror
Since the focal length of plane mirror is infinity therefore image and object are equidistant from mirror
Distance of first image on left mirror is
[tex]d_1=6.6+6.6=13.2 ft[/tex]
i.e. image is 13.2 ft away from object
Second image
Now the right mirror forms the image of object at distance of 14.1 ft right from right mirror so its image is formed in left mirror at a distance of 34.8 from left mirror
so image distance from person is
[tex]d_2=34.8+6.6=41.4 ft[/tex]
Third image now form image of second image is formed on right mirror at a distance of 55.5 right from right mirror
and its mirror image is formed on left mirror at a distance of 76.2 left
from left mirror
[tex]d_3=76.2+6.6=82.8 ft[/tex]
The distances of the person from the first three images as seen from the left hand mirror are 13.2ft, 41.4ft and 82.8ft respectively.
From the question
The person is 6.60 ft from the left side of the mirror
But the focal length of plane mirror is infinity which means both the image and object are equidistant from mirror
Therefore,the Distance of first image on left wall of the mirror is
D1=6.6+6.6=13.2 ft
where D1 is first distance.
So the image is 13.2 ft away from object.
From the second image,
The right side of the mirror forms the image of object at distance of 14.1 ft right from right mirror .The image is formed from the left mirror at a distance of 34.8 from left mirror.
The person second distance is
d2=34.8+6.6=41.4 ft
where d2 is second distance.
The Third image is formed on right at a distance of 55.5 right from right mirror and the mirror image is formed on left side of the mirror at a distance of 76.2 left
d3=76.3+6.6= 82.8ft.
Refraction of light is the bending of light as it move from one transparent object into another.
Therefore, The distances of the person from the first three images as seen from the left hand mirror are 13.2ft, 41.4ft and 82.8ft respectively.
Learn more about Refraction of light here.
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