Answer:
[tex]d_{2}[/tex] = 33.33 cm
Explanation:
Given:
When mass, [tex]m_{1}[/tex] =21 kg
distance travelled is [tex]d_{1}[/tex] = 140 cm
When mass, [tex]m_{2}[/tex] =5 kg
distance travelled is [tex]d_{2}[/tex] = ?
Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.
Therefore according to the question,
[tex]\frac{d_{1}}{m_{1}}=\frac{d_{2}}{m_{2}}[/tex]
[tex]\frac{140}{21}=\frac{d_{2}}{5}[/tex]
[tex]d_{2}[/tex] = 33.33 cm
Distance travelled is 33.33 cm when mass is 5 kg.
