Answer:
Step-by-step explanation:
Set up null and alternate hypothesis
H0: p =0.05
Ha: p>0.05
(One tailed test at 5% level)
Sample size n =384
Sample proportion p = 46/384 =0.1198
p difference = 0.1198-0.05 =0.0698
Std error = [tex]\sqrt{\frac{0.1198*0.8702}{384} } =0.0165[/tex]
Test statistic = 4.23
p value = 0.000012
Since p<0.05, we reject null hypothesis
There is more than 99.95% probability that proportion is more than 0.05
We accept the claim that the risk has increased.