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7. The According to Wien’s Law (λmax = 3×106/T), what is the temperature of the radiation? Recall that to use this formula, the wavelength must be in nanometers (1nm = 10−9 m) and the temperature will be in Kelvin.

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isyllus

Answer:

According to Wien’s Law:

[tex]\lambda_{peak} = \frac{2.9 \times 10^{6} }{T(K)}[/tex]

where;

[tex]\lambda_{peak}[/tex] is the wavelength

T(K) is the temperature in Kelvin

Putting the values given in the above equation:

[tex]{T(K)} = \frac{2.9 \times 10^{6} }{\lambda_{peak}}[/tex]

[tex]{T(K)} = \frac{2.9 \times 10^{6} }{3 \times 10^{3}}}[/tex]

T(K) = 0.966×[tex]10^{3}[/tex]

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