013 (part 2 of 2) 1.0 points Consider a cube whose sides are 0.514 m long. How many kg of sand would it take for the total surface area of all the grains of sand to equal the surface area of the cube? Answer in units of kg.

Respuesta :

Answer:

Answer:

Assuming you´re using washed sand: m=217.9kg

Explanation:

First we will define what volume and what density are:

The volume is the quantity of space an object or substance could use

The density is more like a comparison between the amount of matter to the space a substance occupies

In order to find how much is the volume the cube occupies we will use the next equation:

[tex]V=(S)^3[/tex] where V is Volume and S are the sides length, then we will have:

[tex]V=(0.514m)^3[/tex]

In this case the Volume will be equal to [tex]0.136m^3[/tex]

Now that we have how much is the quantity of space the cube occupies we will assume we´re using washed sand, this sand has a density equals to 1602kg/m^3

Let´s keep in mind we will need the sand inside the whole cube. With this information we will use the next equation to find how many kg of sand it would take:

[tex]p=m/V[/tex] where p is the density, m is the mass and V is the volume

[tex]p*V=m[/tex]  

[tex](1602kg/m^3)*(0.136m^3)=m[/tex]

Then the mass of sand we will need to fill the whole cube will be 217.9kg