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During a trial run, race car A starts from rest and accelerates uniformly along a straight level track for a particular interval of time. Race car B also starts from rest and accelerates at the same rate, but for twice the time. At the end of their respective acceleration periods, which of the following statements is true? Car A has traveled a greater distance. Car B has traveled twice as far as A. Car B has traveled four times as far as car A. Both cars have traveled the same distance.

Respuesta :

Answer:Car B has traveled four times as far as car A

Explanation:

Given Both cars start From rest i.e. initial velocity is zero

Let a be the acceleration of cars and t be the time in which A completes the trial and 2t for Car B

Using equation of motion for Car A

[tex]S_a=ut+\frac{1}{2}at^2[/tex]

[tex]S_a=\frac{1}{2}at^2[/tex]

For Car B

[tex]S_b=ut+\frac{1}{2}2t^2[/tex]

[tex]S_b=2at^2[/tex]  

Thus distance traveled by car B is four times the car B

       

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