Answer: The concentration of [tex]H_2SO_4[/tex] comes out to be 0.109 M.
Explanation:
To calculate the concentration of acid, we use the equation given y neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is KOH.
We are given:
[tex]n_1=2\\M_1=?M\\V_1=25.00mL\\n_2=1\\M_2=0.1322M\\V_2=41.22mL[/tex]
Putting values in above equation, we get:
[tex]2\times M_1\times 25=1\times 0.1322\times 41.22\\\\M_1=0.109M[/tex]
Hence, the concentration of [tex]H_2SO_4[/tex] comes out to be 0.109 M
