contestada

When Karl Kaveman adds chilled grog to his new granite mug, he removes 10.9 kJ of energy from the mug. If it has a mass of 625 g and was at 25°C, what is its new temperature? Specific heat capacity of granite = 0.79 J/(g·K)

Respuesta :

Answer:

3°C

Explanation:

We can that heat Q=m[tex]c_p[/tex] dT

Where m is the mass [tex]c_p[/tex] = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

[tex]T_1[/tex] =25°C

[tex]T_2[/tex] we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-[tex]T_2[/tex])

25-[tex]T_2[/tex] =22

[tex]T_2[/tex]=3°C

Answer:

47.08 degree C

Explanation:

H = 10.9 kJ = 10.9 x 1000 J

m = 625 g = 0.625 kg

T1 = 25 degree C

Let the final temperature is T2.

c = 0.79 J/g C = 790 J/kg C

H = m x c x (T2 - T1)

10.9 x 1000 = 0.625 x 790 x  (T2 - 25)

T2 = 47.08 degree C

Otras preguntas