Answer:
The mass of iodine produced will be 79.46 kg .
Explanation:
Let us calculate the mole ratio of potassium and iodine formed when first sample was decomposed.
Atomic mass of potassium =39 g/mol
Atomic mass of iodine = 127 g/mol
Moles of K produced = [tex]\frac{mass}{atomicmass}=\frac{13}{39}= 0.33[/tex]
Moles of I produced = [tex]\frac{mass}{atomicmass}=\frac{42.3}{127}= 0.33[/tex]
The mole ration of K :I = 1:1
The moles of K produced by second sample = [tex]\frac{mass}{molarmass}=\frac{24.4X10^{3}}{39}= 0.626X10^{3} mol[/tex]
The same moles of I must have been produced.
The mass of Iodine produced = moles X atomic mass = 0.626 X 127=79.46 kg
79.46kg of Iodine will be produced in the reaction.
These are substances which can't be broken down into smaller matter and is usually very pure.
Atomic mass of potassium =39 g/mol
Atomic mass of iodine = 127 g/mol
Moles of K produced = ?
Moles of I produced = ?
The moles of K produced = mass/molar mass
= 13/39
= 0.33
Moles of I produced= mass/molar mass
=42.3/127
= 0.33
Mole ratio of K:I = 1:1
The moles of K produced by second sample = mass/molar mass =
= 24.4 × 10³ / 39 = 0.626mol
The mass of Iodine produced = moles X atomic mass
= 0.626 X 127= 79.46 kg
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