Answer:
Option A, [tex]0.49[/tex]
Explanation:
As per Hardy Weinberg equation -
[tex]p^2[/tex] is the frequency of occurrence of genotype [tex]A_1A_1[/tex]
The frequency of allele [tex]A_1[/tex] will be equal to square root of frequency of [tex]\sqrt{p_2}[/tex]
Substituting the given value in above equation, we get -
Frequency of allele [tex]A_1= \sqrt{p^2}[/tex]
Frequency of allele [tex]A_1 = \sqrt{0.17}[/tex]
Frequency of allele [tex]A_1= 0.412[/tex]
So the nearest option is option [tex]0.49[/tex], i.e option A