Answer with explanation:
We have to find two integers m and n such that, m>1000, and m's last 3 digits are 007, and n is a positive integer such that they are relatively Prime to each other.
⇒4007 is a prime number.And there can be many positive numbers prime to 4007 which are 2,3,5,7,11,13,17,19,23,29,31,37.................
→So, Ordered pairs are=(4007,2),(4007,3),..........