Answer:
The type of interference the person perceives is a Constructive Interference
Explanation:
Before we solve the problem we need to clarify some concepts:
There are two types of Interference, the Constructive and the Destructive interference
The Constructive Interference happens if the difference between the waves movement is equal to an even semi-wavelength number
The Destructive Interference is the opposite than the Constructive Interference, it happens if the difference between the waves movement is equal to an odd semi-wavelength number
Taking the above into account let´s proceed to solve the problem.
First, we will need to find how much the wavelength is (we will call it l), we know the frequency f=200Hz, we also know the speed of sound is v=330m/s. We will use the next equation:
[tex]l=v/f[/tex] then we get that [tex]l=1.65m[/tex]
In order to find the semi-wavelength we must divide by 2 the previous result, in this case the semi-wavelength will be:
[tex]l/2=0.825m[/tex]
Now, we find the difference between the waves movement, which is the difference between both distances, this difference will be called d and we will find it this way:
[tex]d=4.95m-1.65m[/tex] then d=3.3m
After this, we will do a relation between the distance and the semi-wavelength in order to find what type of interference the person perceives, this way:
[tex](d)/(l/2)[/tex] then, we have a relation equals to 4. As it´s an even number, we determine the interference is a Constructive Interference
The person would experience a Constructive Interference.
A constructive interference is a situation where the resultant wave felt is bigger than either of the two original.
Now, the difference between the waves movement, which is the difference between both distances, assuming we take d as the difference, we have
4.95m - 1.65m = 3.30m. This would serve as the constructive interference.
Learn more about Constructive Interference here:
brainly.com/question/2166481
