Answer:
Probability of drawing non defective bulb
=90/100×89/99×88/98×...........×82/92..........(i)=90/100×89/99×88/98×...........×82/92..........(i)
Now the probability of drawing at least one bulb will be defective
=1−(i)=1−90/100×89/99×88/98×...........×82/92
1−(90/100⋅89/99⋅…⋅83/93)
