Explanation:
Hi, when mixing cadmium chloride (CdCl2) and sodium sulfide (Na2S) the cadmium displaces the sodium from the salt making an insoluble salt that precipitates, named cadmium sulfide (CdS).
1) The global molecular equation for this reaction is:
CdCl2 (aq) + Na2S (aq) → CdS (s) + 2 NaCl (aq)
2) The ionic hemireactions are:
Na+(aq) + Cl-(aq) → NaCl (aq)
Cd+2(aq) + S-2(aq) → CdS (s)
3) The net ionic equation is:
2 Na+(aq) + 2 Cl-(aq) + Cd+2(aq) + S-2(aq) → NaCl (aq) + CdS (s)
When aqueous solutions of cadmium chloride and sodium sulfide are mixed, a precipitate of cadmium sulfide forms, leaving soluble sodium chloride in the solution. The corresponding equations are:
Molecular equation: CdCl₂(aq) + Na₂S(aq) ⇒ CdS(s) + 2 NaCl(aq)
Ionic equation: Cd²⁺(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + S²⁻(aq) ⇒ CdS(s) + 2 Na⁺(aq) + 2 Cl⁻(aq)
Net ionic equation: Cd²⁺(aq) + S²⁻(aq) ⇒ CdS(s)
Let's consider the molecular equation for the reaction between aqueous cadmium chloride and aqueous sodium sulfide to form a precipitate of cadmium sulfide and aqueous sodium chloride. This is a double displacement reaction.
CdCl₂(aq) + Na₂S(aq) ⇒ CdS(s) + 2 NaCl(aq)
The ionic equation includes all the ions and insoluble species.
Cd²⁺(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + S²⁻(aq) ⇒ CdS(s) + 2 Na⁺(aq) + 2 Cl⁻(aq)
The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and the insoluble species.
Cd²⁺(aq) + S²⁻(aq) ⇒ CdS(s)
When aqueous solutions of cadmium chloride and sodium sulfide are mixed, a precipitate of cadmium sulfide forms, leaving soluble sodium chloride in the solution. The corresponding equations are:
Molecular equation: CdCl₂(aq) + Na₂S(aq) ⇒ CdS(s) + 2 NaCl(aq)
Ionic equation: Cd²⁺(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + S²⁻(aq) ⇒ CdS(s) + 2 Na⁺(aq) + 2 Cl⁻(aq)
Net ionic equation: Cd²⁺(aq) + S²⁻(aq) ⇒ CdS(s)
You can learn more about double displacement reactions here: https://brainly.com/question/23008924
