contestada

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle and it has a length of 3 and a width of x-2 .Find the size of the area that was not painted

Help me please

Find the area of a rectangle that has the length of 2x3 and the width of x Someone painted an interior area of the rectangle and it has a length of 3 and a widt class=

Respuesta :

calculista

Answer:

The area that was not painted is [tex](2x^{2}-6x+6)\ units^{2}[/tex]

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

[tex]A=LW[/tex]

In this problem we have

[tex]L=2x-3[/tex]

[tex]W=x[/tex]

substitute

[tex]A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}[/tex]

step 2

Find the area that was painted

[tex]A=(3)(x-2)\\A=(3x-6)\ units^{2}[/tex]

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

[tex]A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}[/tex]

Otras preguntas