Answer:
Part 1) The algebraic expression is equal to [tex]1.10(n-1)[/tex] or [tex]1.10n-1.10[/tex]
Part 2) The algebraic expression is equal to [tex]\frac{1.10}{n}[/tex]
Step-by-step explanation:
Part 1) we have (n-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)
[tex]1.10(n-1)[/tex]
Distributed
[tex]1.10n-1.10[/tex]
Part 2) we have n^(-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)
Remember that
[tex]n^{-1}=\frac{1}{n}[/tex]
so
[tex]1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}[/tex]
