Answer:
71.56°
Explanation:
I₀ = Intensity of unpolarized light
θ = Angle between the axis of the filter and polarization direction
Intensity of polarzied light
[tex]I=I_0cos\theta[/tex]
Here, the light that is transmitted is reduced by 10% that means
I=0.1I₀
So,
[tex]0.1I_0=I_0cos^2\theta\\\Rightarrow cos^2\theta =0.1\\\Rightarrow cos\theta =0.316\\\Rightarrow \theta= cos^{-1}0.316\\\Rightarrow \theta=71.56^{\circ}[/tex]
∴ The angle between the axes of the polarizer and the analyzer is 71.56°
