Respuesta :
Answer:
The formula of the conjugate base anion would be CH₃CH₂CH₂CH₂CH₂COO⁻.
Kindly see the attachment for the reaction.
Explanation:
Hexanoic acid on reaction with water gets deprotonated and leads to the formation of carboxylate anion.
Hexanoic acid is a proton donor when water abstracts proton from hexanoic acid. Also water accepts a proton donated by hexanoic acid so water is a proton acceptor.
The bronsted -lowry acid base concepts states that any substance that donates a proton or has the capacity is a bronsted acid and any substance which has the capacity to accept proton is a bronsted base.
So here in this case Hexanoic acid is a proton donor as it is donating its acidic proton and water is acting as a bronsted base as it is accepting the proton.
As soon as an acid is deprotonated it generates its conjugate base anion.
As soon as an base is protonated it generates a its conjugate acid .
In this reaction :
CH₃CH₂CH₂CH₂CH₂COOH +H₂O→CH₃CH₂CH₂CH₂CH₂COO⁻+H₃O⁺
In left hand side hexanoic acid is a bronsted acid and H₂O is the bronste base.
In right hand side the CH₃CH₂CH₂CH₂CH₂COO⁻ acts a bronsted base and H₃O⁺ acts as a bronsted acid.
Monoprotic weak acids are the acids that are capable of donating a single proton. The formula for the conjugate base of the weak acid will be [tex]\rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COO^{-}.[/tex]
What is a conjugate base?
A conjugate base is a substance produced after accepting the proton or the hydrogen atom from the weak acid in the solution or the reaction.
The conjugate base of the monoprotic weak hexanoic acid will be [tex]\rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COO^{-}[/tex] and hydronium ion will be the conjugate acid.
The reaction of hexanoic acid with water is shown as,
[tex]\rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COOH + H_{2}O \rightarrow \rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COO^{-} +H_{3}O^{+}[/tex]
Here, [tex]\rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COOH[/tex] is the bronsted acid, water is bronsted base, [tex]\rm CH_{3}CH_{2}CH_{2}CH_{2}CH_{2}COO^{-}[/tex] is the conjugate base, [tex]\rm H_{3}O^{+}[/tex] is the conjugate acid of Bronsted base (water).
In this case, hexanoic acid is a bronsted acid as it is a proton donor and water is a bronsted base as it is accepting hydrogen atoms or protons.
Therefore, hexanoic acid is bronsted acid and water is a bronsted base.
Learn more about bronsted acid and base here:
https://brainly.com/question/7036745
