Answer:
The increases depth of the water is 0.021 m.
Explanation:
Given that,
One side of square = 5.8 m
Depth = 4.2 m
Temperature = 24°C
Coefficient of volume expansion for water[tex]\beta = 210\times10^{-6}\ /^{\circ}C[/tex]
We need to calculate the volume of the pool
[tex]V= 5.8\times5.8\times4.2[/tex]
[tex]V=141.288\ m^3[/tex]
Using formula of coefficient of volume expansion
[tex]\Delta V=\Beta V_{0}\times\Delta T[/tex]
If the temperature changes by 24 degrees C during the afternoon,
[tex]5.8\times5.8\times h=210\times10^{-6}\times141.288\times24[/tex]
[tex]h=\dfrac{210\times10^{-6}\times141.288\times24}{5.8\times5.8}[/tex]
[tex]h=0.021\ m[/tex]
Hence. The increases depth of the water is 0.021 m.
