Answer:
The fire hose be located 59.80 m away to hit the highest possible fire.
Explanation:
Vertical velocity = 25 sin35 = 14.34 m/s
Acceleration = -9.81m/s²
At maximum height , final vertical velocity = 0 m/s
We have v = u + at
Substituting
0 = 14.34 - 9.81 x t
t = 1.46 s
Time of flight of water = 2 x 1.46 = 2.92 s
Horizontal velocity = 25 cos35 = 20.48 m/s
Horizontal displacement = 20.48 x 2.92 = 59.80 m
So, the fire hose be located 59.80 m away to hit the highest possible fire.