Answer:
Density of unknown material = 3.86 g/cm³
Explanation:
Mass of unknown material, M = 54 gm
The object occupied 14 gm of water.
Volume of unknown material = Volume of 14 gm of water.
Density of water = 1 gm/cm³
Volume of 14 gm of water
[tex]V=\frac{14}{1}=14cm^3[/tex]
Volume of unknown material, V = Volume of 14 gm of water = 14 cm³
Density of unknown material
[tex]\rho =\frac{M}{V}=\frac{54}{14}=3.86g/cm^3[/tex]
